(x^2-3x-10)=(2-2x)

Solution for (x^2-3x-10)=(2-2x) equation:

(x^2-3x-10)=(2-2x)

We move all terms to the left:

(x^2-3x-10)-((2-2x))=0

We add all the numbers together, and all the variables

(x^2-3x-10)-((-2x+2))=0

We get rid of parentheses

x^2-3x-((-2x+2))-10=0


We calculate terms in parentheses: -((-2x+2)), so:

(-2x+2)

We get rid of parentheses

-2x+2

Back to the equation:

-(-2x+2)


We get rid of parentheses

x^2-3x+2x-2-10=0

We add all the numbers together, and all the variables

x^2-1x-12=0

a = 1; b = -1; c = -12;
Δ = b2-4ac
Δ = -12-4·1·(-12)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-7}{2*1}=\frac{-6}{2}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+7}{2*1}=\frac{8}{2}
=4
$